F(2x-1)=x^2-x+3

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Solution for F(2x-1)=x^2-x+3 equation: 



(2F-1)=F^2-F+3

We move all terms to the left:

(2F-1)-(F^2-F+3)=0

We get rid of parentheses

-F^2+2F+F-1-3=0

We add all the numbers together, and all the variables

-1F^2+3F-4=0

a = -1; b = 3; c = -4;
Δ = b2-4ac
Δ = 32-4·(-1)·(-4)
Δ = -7
Delta is less than zero, so there is no solution for the equation

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